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The solution that gives the smaller angle between hours & mins hands By sun4emicrosoftinterview on Wednesday, March 21, 2007 (UMST)

int getAngleBetweenClockHands(int hour,int mins){     int baseVal = 0;     baseVal = abs((hour * 5) - (mins)) * 6;     baseVal = baseVal > (360-baseVal)?(360-baseVal):baseVal;        return baseVal; }   Reply to this Comment Average Rating:

correct answer By JeremyCAFE on Saturday, April 21, 2007 (UMST)

result = abs((hour * 30) + (min * .5) - (min * 6)) if(result > 180) result = abs(result - 360) Reply to this Comment Average Rating:

elegant solution By jagatsastry on Thursday, August 30, 2007 (UMST)

int getAngle(int hour, int min) { int baseVal; return (baseval=(abs(hour*5-min)*6))<180?baseval:(360-baseval); } Reply to this Comment

elegant solution By jagatsastry on Thursday, August 30, 2007 (UMST)

int getAngle(int hour, int min)<br> {<br> int baseVal;<br> return (baseval=(abs(hour*5-min)*6))<180?baseval:(360-baseval);<br> } Reply to this Comment

elegant solution By jagatsastry on Thursday, August 30, 2007 (UMST)

int getAngle(int hour, int min)<br> {<br> int baseVal;<br> return (baseval=(abs(hour*5-min)*6))<180?baseval:(360-baseval);<br> } Reply to this Comment

Angle between hour and minute hands By srmoody on Sunday, October 07, 2007 (UMST)

I know I must have missed something, because my submission doesnt look like most of the submissions, yet my testing indicated that this works... so please feel free to point out the mistakes I have made, or why this will not work in every case. Thanks   Formula: degrees = abs((hour * 5) - minutes) * 6   int GetDegrees(int hour, int minutes) {       int degrees;       int minutesInTheHour = hour * 5;       degrees = abs(minutesInTheHour - minutes) * 6;         return degrees; } Reply to this Comment

A one-line solution By septembersun on Tuesday, December 04, 2007 (UMST)

Found a common mistake in all the previous posts: None of them considered the case when the hours hand would be pointing at 12. Here is a solution accomodating this possibility: float getAngle(int hours, int mins) { return abs( ((hours%12)*30+float(mins)/2) - (mins*6) ); } Reply to this Comment

A one-line solution By septembersun on Tuesday, December 04, 2007 (UMST)

Found a common mistake in all the previous posts: None of them considered the case when the hours hand would be pointing at 12. Here is a solution accommodating this possibility: float getAngle(int hours, int mins) { return abs( ((hours%12)*30+float(mins)/2) - (mins*6) ); } Reply to this Comment

another one By chauhan on Sunday, January 20, 2008 (UMST)

double hour, min; hour=5; min=45; double hourAngle, minAngle; minAngle = 360/60 * min; hourAngle = 360/60 * (5*(double)hour); hourAngle += 360/(double)12 * (min/60); cout<<" minAngle: "<< minAngle<<" hourAngle: "<<hourAngle; Reply to this Comment

exact approach.- taking the little diference from the hour hand advancement By ivanr on Thursday, January 24, 2008 (UMST)

if(hour == 12)hour=0;   if (hour*30>= min*6)angle = (hour*30)-(min*6)+(min*(0.5));     else angle = (min*6)-(hour*6)-(min*(0.5)); Reply to this Comment

another solution By bluerok on Monday, February 11, 2008 (UMST)

public static double getAngle(int hour, int mins) { if (hour == mins) return 0; double theta = ((double)Math.abs(hour - mins) / 12) * 360; if (theta > 180) return 360 - theta; else return theta; } Reply to this Comment

Answer By kandukondein on Sunday, February 17, 2008 (UMST)

int GetClockAngle(int Hr,int Min) {    int hDegree =Hr*30;    int mDegree= Min*6;    if(hDegree > 180) hDegree = 360 - hDegree;    else if(mDegree > 180) mDegree = 360 - mDegree;   int Degree = hDegree + mDegree ;   if(Degree > 180) Degree=360 - Degree;   return Degree; } Reply to this Comment

Corrected one By kandukondein on Sunday, February 17, 2008 (UMST)

Oops found a bug...The Corrected code      int hDegree =Hr*30;    int mDegree= Min*6;   int Degree = 0;   Degree=(hDegree - mDegree);    if(Degree < 0) Degree = -Degree;  if(Degree>180) Degree=360-Degree;   return Degree; Reply to this Comment

Hours, Minutes By imnotageek on Monday, August 04, 2008 (UMST)

( (12 - hours ) * 5 - ( minutes / 60 ) * 5 + minutes ) * 6 Reply to this Comment

Simple answer By aravind on Thursday, October 09, 2008 (UMST)

if(hour==12) hour=12;   angle=(30*hour)+(5.5*min);   if(angle>180) { angle=-1*(360-angle); cout<<angle; } else cout<<angle; Reply to this Comment

Simple answer By aravind on Thursday, October 09, 2008 (UMST)

if(hour==12) hour=0;   angle=(30*hour)+(5.5*min);   if(angle>180) { angle=-1*(360-angle); cout<<angle; } else cout<<angle; Reply to this Comment